Transfer regularity in L to help you volume in mL and so the gadgets to possess density (g mL -step one ) is consistent:

Created | By: Kevin García | julio 1, 2022
 
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Transfer regularity in L to help you volume in mL and so the gadgets to possess density (g mL -step one ) is consistent:

(ii) Have you ever mulatto dating app utilized the correct number of high data? thickness (step one.03 ) possess step 3 extreme data regularity (1) possess step 1 tall figure When multiplying otherwise splitting, what number of tall numbers on the result is an identical as the least quantity of high figures in the terms and conditions made use of, therefore we are rationalized in using step 1 high shape. All of our address (ten30) enjoys cuatro significant numbers! Since the audience is simply rationalized in making use of 1 significant contour, we could provide the respond to just like the a lot of grams, nevertheless best answer should be to explore medical notation and you may write step one ? 10 step three grams

(iii) Can be your respond to probable? Carry out good “rough” calculation: thickness ≈ 1 grams mL -step 1 step one mL regarding whole milk has actually scores of on the step 1 grams 1 L (a lot of mL) of dairy enjoys scores of about one thousand ? 1 = 1000 grams Since this rough calculation is nearly the new meticulously calculated really worth having mass we are reasonably positive that our very own respond to is correct.

Matter 5. Within 25°C and you can step one atm pressure, diamond have a density out of step three.5 g cm -3 . Determine the amount from inside the cm step three from 0.fifty grams off diamond at twenty-five°C and step one automatic teller machine stress.

3.5 grams cm -step three ? V (cm 3 ) = V(cm step three ) ? 0.50 grams ? V (cm step 3 ) step three.5 g cm -3 ? V (cm step 3 ) = 0.fifty g

[ step three.5 g cm -3 ? V (cm step three )] ? 3.5 grams cm -3 = 0.50 g ? step 3.5 g cm -step three V (cm 3 ) = 0.fifty ? step 3.5 (cm -step 3 ) = 0.fourteen cm step three

Would an effective “rough” calculation: occurrence ≈ 5 grams cm -step three step one cm -3 out of diamond provides quite a few about 5 grams

(ii) Have you ever used the right level of high rates? occurrence (step three.5) enjoys dos tall numbers volume (0.50) features dos extreme numbers When multiplying otherwise isolating, the amount of significant numbers regarding the result is an equivalent due to the fact minimum number of extreme rates in the terminology utilized, therefore we is actually justified in using dos extreme rates. The address (0.14) has actually dos tall figures

(iii) Is your answer plausible? 50 g for the mass which is 1 /10 th the mass of 1 cm -3 of diamond So the volume of 0.50 g of diamond will 1 /10 th the volume that is V = 1 /10 ? 1 cm 3 = 0.1 cm 3 Since this “rough” answer is about the same as our carefully calculated answer we are reasonably confident that our answer is correct.

Question 6. At the twenty-five°C and step 1 automatic teller machine tension, ethylene glycol features a density of just one.11 g mL -1 . Estimate the quantity in mL off 0.025 kilogram of ethylene glycol in the twenty-five°C and you can step one automatic teller machine tension.

Convert mass within the kg so you can bulk into the g to help you be consistent which have devices of density (g mL -step 1 ):

V (mL) ? step 1.eleven (g mL -step one ) = V (mL) ? twenty five (g) ? V (mL) V (mL) ? step 1.eleven (g mL -step 1 ) = twenty five (g)

Practical question gives us 0

[V (mL) ? step one.eleven (g mL -step one ) ] ? step 1.11 (g mL -step one ) = twenty five (g) ? 1.eleven ( g mL -step 1 ) V (mL) = twenty-five ? step one.11 (mL -step one ) = 23 mL

(ii) Maybe you have used the right level of high rates? size (0.025) provides dos extreme data occurrence (1.11) have 3 tall data Whenever multiplying or isolating, how many high figures about outcome is an equivalent since the very least amount of significant rates throughout the terms put, therefore we is warranted in making use of dos extreme numbers. The respond to (25) possess 2 tall rates

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